Base | Representation |
---|---|
bin | 11101000000100110100… |
… | …110011100101110101111 |
3 | 21001120121022100120221001 |
4 | 131000212212130232233 |
5 | 230130203141014303 |
6 | 4123450150021131 |
7 | 264012045100132 |
oct | 35004646345657 |
9 | 7046538316831 |
10 | 1993512438703 |
11 | 6a9497889a85 |
12 | 2824333477a7 |
13 | 115cab47a0c6 |
14 | 6c6b5006219 |
15 | 36cc868731d |
hex | 1d02699cbaf |
1993512438703 has 2 divisors, whose sum is σ = 1993512438704. Its totient is φ = 1993512438702.
The previous prime is 1993512438689. The next prime is 1993512438751. The reversal of 1993512438703 is 3078342153991.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1993512438703 - 221 = 1993510341551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1993512438103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 996756219351 + 996756219352.
It is an arithmetic number, because the mean of its divisors is an integer number (996756219352).
Almost surely, 21993512438703 is an apocalyptic number.
1993512438703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1993512438703 is an equidigital number, since it uses as much as digits as its factorization.
1993512438703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 55.
The spelling of 1993512438703 in words is "one trillion, nine hundred ninety-three billion, five hundred twelve million, four hundred thirty-eight thousand, seven hundred three".
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