Base | Representation |
---|---|
bin | 11101000001000000111… |
… | …111111110010010111001 |
3 | 21001121202011202011201112 |
4 | 131001000333332102321 |
5 | 230132110031244101 |
6 | 4124002130530105 |
7 | 264026033502026 |
oct | 35010077762271 |
9 | 7047664664645 |
10 | 1993955337401 |
11 | 6a96a4895365 |
12 | 282537736935 |
13 | 11604c15b741 |
14 | 6c717b7654d |
15 | 36d024c16bb |
hex | 1d040ffe4b9 |
1993955337401 has 2 divisors, whose sum is σ = 1993955337402. Its totient is φ = 1993955337400.
The previous prime is 1993955337289. The next prime is 1993955337403. The reversal of 1993955337401 is 1047335593991.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1931824789801 + 62130547600 = 1389901^2 + 249260^2 .
It is a cyclic number.
It is not a de Polignac number, because 1993955337401 - 218 = 1993955075257 is a prime.
Together with 1993955337403, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1993955337403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 996977668700 + 996977668701.
It is an arithmetic number, because the mean of its divisors is an integer number (996977668701).
Almost surely, 21993955337401 is an apocalyptic number.
It is an amenable number.
1993955337401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1993955337401 is an equidigital number, since it uses as much as digits as its factorization.
1993955337401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13778100, while the sum is 59.
The spelling of 1993955337401 in words is "one trillion, nine hundred ninety-three billion, nine hundred fifty-five million, three hundred thirty-seven thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •