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19983913 is a prime number
BaseRepresentation
bin100110000111…
…0111000101001
31101121021202221
41030032320221
520103441123
61552154041
7331601065
oct114167051
941537687
1019983913
111030a234
126838921
1341a9001
142922aa5
151b4b25d
hex130ee29

19983913 has 2 divisors, whose sum is σ = 19983914. Its totient is φ = 19983912.

The previous prime is 19983911. The next prime is 19983917. The reversal of 19983913 is 31938991.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11614464 + 8369449 = 3408^2 + 2893^2 .

It is a cyclic number.

It is not a de Polignac number, because 19983913 - 21 = 19983911 is a prime.

It is a super-3 number, since 3×199839133 (a number of 23 digits) contains 333 as substring.

Together with 19983911, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 19983913.

It is not a weakly prime, because it can be changed into another prime (19983911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9991956 + 9991957.

It is an arithmetic number, because the mean of its divisors is an integer number (9991957).

Almost surely, 219983913 is an apocalyptic number.

It is an amenable number.

19983913 is a deficient number, since it is larger than the sum of its proper divisors (1).

19983913 is an equidigital number, since it uses as much as digits as its factorization.

19983913 is an evil number, because the sum of its binary digits is even.

The product of its digits is 52488, while the sum is 43.

The square root of 19983913 is about 4470.3370119041. The cubic root of 19983913 is about 271.3689640774.

The spelling of 19983913 in words is "nineteen million, nine hundred eighty-three thousand, nine hundred thirteen".