Base | Representation |
---|---|
bin | 1001000101101001000001… |
… | …01011101100010110001101 |
3 | 2121202112212011221021220101 |
4 | 10202310200223230112031 |
5 | 10104413320433344122 |
6 | 110300555131451101 |
7 | 4131604462642426 |
oct | 442644053542615 |
9 | 77675764837811 |
10 | 19985031153037 |
11 | 6405671093835 |
12 | 22a92965b6a91 |
13 | b1c771054742 |
14 | 4d13d022664d |
15 | 249ccab77027 |
hex | 122d20aec58d |
19985031153037 has 2 divisors, whose sum is σ = 19985031153038. Its totient is φ = 19985031153036.
The previous prime is 19985031152987. The next prime is 19985031153047. The reversal of 19985031153037 is 73035113058991.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19268140423401 + 716890729636 = 4389549^2 + 846694^2 .
It is a cyclic number.
It is not a de Polignac number, because 19985031153037 - 231 = 19982883669389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19985031153047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9992515576518 + 9992515576519.
It is an arithmetic number, because the mean of its divisors is an integer number (9992515576519).
Almost surely, 219985031153037 is an apocalyptic number.
It is an amenable number.
19985031153037 is a deficient number, since it is larger than the sum of its proper divisors (1).
19985031153037 is an equidigital number, since it uses as much as digits as its factorization.
19985031153037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3061800, while the sum is 55.
The spelling of 19985031153037 in words is "nineteen trillion, nine hundred eighty-five billion, thirty-one million, one hundred fifty-three thousand, thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •