19993000613 has 4 divisors (see below), whose sum is σ = 19995779628. Its totient is φ = 19990221600.

The previous prime is 19993000597. The next prime is 19993000679. The reversal of 19993000613 is 31600039991.

19993000613 = 99982² + 99983².

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31600039991 = 13 ⋅2430772307.

It can be written as a sum of positive squares in 2 ways, for example, as 9996400324 + 9996600289 = 99982^2 + 99983^2 .

It is a cyclic number.

It is not a de Polignac number, because 19993000613 - 2⁴ = 19993000597 is a prime.

It is a super-2 number, since 2×19993000613² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19993000213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1378688 + ... + 1393113.

It is an arithmetic number, because the mean of its divisors is an integer number (4998944907).

Almost surely, 2^19993000613 is an apocalyptic number.

19993000613 is the 99983-rd centered square number.

It is an amenable number.

19993000613 is a deficient number, since it is larger than the sum of its proper divisors (2779015).

19993000613 is an equidigital number, since it uses as much as digits as its factorization.

19993000613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2779014.

The product of its (nonzero) digits is 39366, while the sum is 41.

The spelling of 19993000613 in words is "nineteen billion, nine hundred ninety-three million, six hundred thirteen", and thus it is an aban number.