Base | Representation |
---|---|
bin | 10010100111101011… |
… | …001111101010010101 |
3 | 1220121100100122212121 |
4 | 102213223033222111 |
5 | 311421202004342 |
6 | 13103515215541 |
7 | 1305305462323 |
oct | 224753175225 |
9 | 56540318777 |
10 | 19993000597 |
11 | 852a589299 |
12 | 3a5b7475b1 |
13 | 1b680c6a8b |
14 | d793c2d13 |
15 | 7c0337067 |
hex | 4a7acfa95 |
19993000597 has 2 divisors, whose sum is σ = 19993000598. Its totient is φ = 19993000596.
The previous prime is 19993000571. The next prime is 19993000679. The reversal of 19993000597 is 79500039991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19985194161 + 7806436 = 141369^2 + 2794^2 .
It is an emirp because it is prime and its reverse (79500039991) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19993000597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19993004597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9996500298 + 9996500299.
It is an arithmetic number, because the mean of its divisors is an integer number (9996500299).
Almost surely, 219993000597 is an apocalyptic number.
It is an amenable number.
19993000597 is a deficient number, since it is larger than the sum of its proper divisors (1).
19993000597 is an equidigital number, since it uses as much as digits as its factorization.
19993000597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 688905, while the sum is 52.
The spelling of 19993000597 in words is "nineteen billion, nine hundred ninety-three million, five hundred ninety-seven", and thus it is an aban number.
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