Base | Representation |
---|---|
bin | 10010100111101011… |
… | …001111101011100111 |
3 | 1220121100100122222122 |
4 | 102213223033223213 |
5 | 311421202010204 |
6 | 13103515220155 |
7 | 1305305462501 |
oct | 224753175347 |
9 | 56540318878 |
10 | 19993000679 |
11 | 852a589363 |
12 | 3a5b74765b |
13 | 1b680c6b22 |
14 | d793c2d71 |
15 | 7c03370be |
hex | 4a7acfae7 |
19993000679 has 2 divisors, whose sum is σ = 19993000680. Its totient is φ = 19993000678.
The previous prime is 19993000597. The next prime is 19993000793. The reversal of 19993000679 is 97600039991.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19993000679 - 216 = 19992935143 is a prime.
It is a super-2 number, since 2×199930006792 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 19993000679.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19993009679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9996500339 + 9996500340.
It is an arithmetic number, because the mean of its divisors is an integer number (9996500340).
Almost surely, 219993000679 is an apocalyptic number.
19993000679 is a deficient number, since it is larger than the sum of its proper divisors (1).
19993000679 is an equidigital number, since it uses as much as digits as its factorization.
19993000679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 826686, while the sum is 53.
The spelling of 19993000679 in words is "nineteen billion, nine hundred ninety-three million, six hundred seventy-nine", and thus it is an aban number.
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