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19995497 is a prime number
BaseRepresentation
bin100110001000…
…1101101101001
31101121212122222
41030101231221
520104323442
61552323425
7331646624
oct114215551
941555588
1019995497
1110317a05
126843575
1341b1372
142926dbb
151b4e8d2
hex1311b69

19995497 has 2 divisors, whose sum is σ = 19995498. Its totient is φ = 19995496.

The previous prime is 19995491. The next prime is 19995523. The reversal of 19995497 is 79459991.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19616041 + 379456 = 4429^2 + 616^2 .

It is a cyclic number.

It is not a de Polignac number, because 19995497 - 26 = 19995433 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (19995491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9997748 + 9997749.

It is an arithmetic number, because the mean of its divisors is an integer number (9997749).

Almost surely, 219995497 is an apocalyptic number.

It is an amenable number.

19995497 is a deficient number, since it is larger than the sum of its proper divisors (1).

19995497 is an equidigital number, since it uses as much as digits as its factorization.

19995497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 918540, while the sum is 53.

The square root of 19995497 is about 4471.6324759533. The cubic root of 19995497 is about 271.4213884262.

The spelling of 19995497 in words is "nineteen million, nine hundred ninety-five thousand, four hundred ninety-seven".