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1999610131 is a prime number
BaseRepresentation
bin111011100101111…
…1010000100010011
312011100121201102111
41313023322010103
513043400011011
6530230330151
7100360256101
oct16713720423
95140551374
101999610131
11936800762
124797b9957
1325b36ba7c
1414d7d6c71
15ba837121
hex772fa113

1999610131 has 2 divisors, whose sum is σ = 1999610132. Its totient is φ = 1999610130.

The previous prime is 1999610113. The next prime is 1999610149. The reversal of 1999610131 is 1310169991.

Together with previous prime (1999610113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1999610113) and next prime (1999610149).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1999610131 is a prime.

It is a super-2 number, since 2×19996101312 = 7996881351995674322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1999610191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999805065 + 999805066.

It is an arithmetic number, because the mean of its divisors is an integer number (999805066).

Almost surely, 21999610131 is an apocalyptic number.

1999610131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1999610131 is an equidigital number, since it uses as much as digits as its factorization.

1999610131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 40.

The square root of 1999610131 is about 44717.0004696201. Note that the first 3 decimals coincide. The cubic root of 1999610131 is about 1259.8391772147.

The spelling of 1999610131 in words is "one billion, nine hundred ninety-nine million, six hundred ten thousand, one hundred thirty-one".