Search a number
-
+
199983549653 is a prime number
BaseRepresentation
bin1011101000111111110…
…0101100110011010101
3201010012012022220212022
42322033330230303111
511234031242042103
6231512101302525
720306531060546
oct2721774546325
9633165286768
10199983549653
11778a3555878
1232912104a45
1315b20aac644
149971c3c4cd
155306cc5138
hex2e8ff2ccd5

199983549653 has 2 divisors, whose sum is σ = 199983549654. Its totient is φ = 199983549652.

The previous prime is 199983549617. The next prime is 199983549671. The reversal of 199983549653 is 356945389991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 153226839364 + 46756710289 = 391442^2 + 216233^2 .

It is a cyclic number.

It is not a de Polignac number, because 199983549653 - 212 = 199983545557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199983543653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99991774826 + 99991774827.

It is an arithmetic number, because the mean of its divisors is an integer number (99991774827).

Almost surely, 2199983549653 is an apocalyptic number.

It is an amenable number.

199983549653 is a deficient number, since it is larger than the sum of its proper divisors (1).

199983549653 is an equidigital number, since it uses as much as digits as its factorization.

199983549653 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 283435200, while the sum is 71.

The spelling of 199983549653 in words is "one hundred ninety-nine billion, nine hundred eighty-three million, five hundred forty-nine thousand, six hundred fifty-three".