Base | Representation |
---|---|
bin | 10010101000000010… |
… | …001010110101101001 |
3 | 1220121202122222102202 |
4 | 102220002022311221 |
5 | 311424221311103 |
6 | 13104252105545 |
7 | 1305410532023 |
oct | 225002126551 |
9 | 56552588382 |
10 | 19999010153 |
11 | 8532a13371 |
12 | 3a617652b5 |
13 | 1b6941c225 |
14 | d7a109013 |
15 | 7c0b22988 |
hex | 4a808ad69 |
19999010153 has 2 divisors, whose sum is σ = 19999010154. Its totient is φ = 19999010152.
The previous prime is 19999010149. The next prime is 19999010203. The reversal of 19999010153 is 35101099991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19997636569 + 1373584 = 141413^2 + 1172^2 .
It is an emirp because it is prime and its reverse (35101099991) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19999010153 - 22 = 19999010149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 19999010098 and 19999010107.
It is not a weakly prime, because it can be changed into another prime (19999010123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9999505076 + 9999505077.
It is an arithmetic number, because the mean of its divisors is an integer number (9999505077).
Almost surely, 219999010153 is an apocalyptic number.
It is an amenable number.
19999010153 is a deficient number, since it is larger than the sum of its proper divisors (1).
19999010153 is an equidigital number, since it uses as much as digits as its factorization.
19999010153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98415, while the sum is 47.
The spelling of 19999010153 in words is "nineteen billion, nine hundred ninety-nine million, ten thousand, one hundred fifty-three".
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