1999980131 has 2 divisors, whose sum is σ = 1999980132. Its totient is φ = 1999980130.

The previous prime is 1999980007. The next prime is 1999980133. The reversal of 1999980131 is 1310899991.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1999980131 - 2¹⁴ = 1999963747 is a prime.

It is a super-2 number, since 2×1999980131² = 7999841048789554322, which contains 22 as substring.

Together with 1999980133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1999980131.

It is not a weakly prime, because it can be changed into another prime (1999980133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999990065 + 999990066.

It is an arithmetic number, because the mean of its divisors is an integer number (999990066).

Almost surely, 2^1999980131 is an apocalyptic number.

1999980131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1999980131 is an equidigital number, since it uses as much as digits as its factorization.

1999980131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 50.

The square root of 1999980131 is about 44721.1374072708. The cubic root of 1999980131 is about 1259.9168776525.

The spelling of 1999980131 in words is "one billion, nine hundred ninety-nine million, nine hundred eighty thousand, one hundred thirty-one".