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199999103 is a prime number
BaseRepresentation
bin10111110101110…
…11111001111111
3111221100000012012
423322323321333
5402144432403
631502401435
74645651523
oct1372737177
9457300165
10199999103
11a2992317
1256b9027b
1332586a85
141c7c1d83
1512858ed8
hexbebbe7f

199999103 has 2 divisors, whose sum is σ = 199999104. Its totient is φ = 199999102.

The previous prime is 199999091. The next prime is 199999127. The reversal of 199999103 is 301999991.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 199999103 - 214 = 199982719 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199999133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99999551 + 99999552.

It is an arithmetic number, because the mean of its divisors is an integer number (99999552).

Almost surely, 2199999103 is an apocalyptic number.

199999103 is a deficient number, since it is larger than the sum of its proper divisors (1).

199999103 is an equidigital number, since it uses as much as digits as its factorization.

199999103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 177147, while the sum is 50.

The square root of 199999103 is about 14142.1039099563. The cubic root of 199999103 is about 584.8026733600.

The spelling of 199999103 in words is "one hundred ninety-nine million, nine hundred ninety-nine thousand, one hundred three".