Base | Representation |
---|---|
bin | 101101011110011001100011… |
… | …001111000100110111001001 |
3 | 222020010220211101001121112102 |
4 | 231132121203033010313021 |
5 | 202203304234133030433 |
6 | 1545211124211323145 |
7 | 60061414000216031 |
oct | 5536314317046711 |
9 | 866126741047472 |
10 | 200001112001993 |
11 | 587a9aa4785965 |
12 | 1a52167b8b04b5 |
13 | 877a040782723 |
14 | 37561695a88c1 |
15 | 181c74b9e64e8 |
hex | b5e6633c4dc9 |
200001112001993 has 2 divisors, whose sum is σ = 200001112001994. Its totient is φ = 200001112001992.
The previous prime is 200001112001989. The next prime is 200001112002007. The reversal of 200001112001993 is 399100211100002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 183042174958864 + 16958937043129 = 13529308^2 + 4118123^2 .
It is a cyclic number.
It is not a de Polignac number, because 200001112001993 - 22 = 200001112001989 is a prime.
It is not a weakly prime, because it can be changed into another prime (200001112000993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100000556000996 + 100000556000997.
It is an arithmetic number, because the mean of its divisors is an integer number (100000556000997).
Almost surely, 2200001112001993 is an apocalyptic number.
It is an amenable number.
200001112001993 is a deficient number, since it is larger than the sum of its proper divisors (1).
200001112001993 is an equidigital number, since it uses as much as digits as its factorization.
200001112001993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 29.
Adding to 200001112001993 its reverse (399100211100002), we get a palindrome (599101323101995).
The spelling of 200001112001993 in words is "two hundred trillion, one billion, one hundred twelve million, one thousand, nine hundred ninety-three".
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