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20000214434113 is a prime number
BaseRepresentation
bin1001000110000101010011…
…01011010100000101000001
32121211000001022221212221221
410203002221223110011001
510110140414343342423
6110311545514115041
74132652646464134
oct443025153240501
977730038855857
1020000214434113
116411052709611
1222b021341ba81
13b21020852c24
144d203091a21b
1524a3b8ae1e5d
hex1230a9ad4141

20000214434113 has 2 divisors, whose sum is σ = 20000214434114. Its totient is φ = 20000214434112.

The previous prime is 20000214434059. The next prime is 20000214434141. The reversal of 20000214434113 is 31143441200002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19433223505969 + 566990928144 = 4408313^2 + 752988^2 .

It is a cyclic number.

It is not a de Polignac number, because 20000214434113 - 237 = 19862775480641 is a prime.

It is not a weakly prime, because it can be changed into another prime (20000214404113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000107217056 + 10000107217057.

It is an arithmetic number, because the mean of its divisors is an integer number (10000107217057).

Almost surely, 220000214434113 is an apocalyptic number.

It is an amenable number.

20000214434113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20000214434113 is an equidigital number, since it uses as much as digits as its factorization.

20000214434113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 20000214434113 its reverse (31143441200002), we get a palindrome (51143655634115).

The spelling of 20000214434113 in words is "twenty trillion, two hundred fourteen million, four hundred thirty-four thousand, one hundred thirteen".