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20000231113 is a prime number
BaseRepresentation
bin10010101000000110…
…110100111011001001
31220121211222000021111
4102220012310323021
5311430024343423
613104334210321
71305424105462
oct225006647311
956554860244
1020000231113
118533677725
123a620539a1
131b69758ba5
14d7a345d69
157c0cb460d
hex4a81b4ec9

20000231113 has 2 divisors, whose sum is σ = 20000231114. Its totient is φ = 20000231112.

The previous prime is 20000231087. The next prime is 20000231123. The reversal of 20000231113 is 31113200002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13261134649 + 6739096464 = 115157^2 + 82092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20000231113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20000231093 and 20000231102.

It is not a weakly prime, because it can be changed into another prime (20000231123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000115556 + 10000115557.

It is an arithmetic number, because the mean of its divisors is an integer number (10000115557).

Almost surely, 220000231113 is an apocalyptic number.

It is an amenable number.

20000231113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20000231113 is an equidigital number, since it uses as much as digits as its factorization.

20000231113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20000231113 its reverse (31113200002), we get a palindrome (51113431115).

It can be divided in two parts, 200002 and 31113, that multiplied together give a palindrome (6222662226).

The spelling of 20000231113 in words is "twenty billion, two hundred thirty-one thousand, one hundred thirteen".