Base | Representation |
---|---|
bin | 101101011110011011011111… |
… | …110101000010111000010011 |
3 | 222020011010020001101021200002 |
4 | 231132123133311002320103 |
5 | 202203323024244031011 |
6 | 1545212111442320215 |
7 | 60061516541551124 |
oct | 5536333765027023 |
9 | 866133201337602 |
10 | 200003202330131 |
11 | 587aa977708382 |
12 | 1a521b6395906b |
13 | 877a2b4865195 |
14 | 37562c705804b |
15 | 181c82029cc3b |
hex | b5e6dfd42e13 |
200003202330131 has 2 divisors, whose sum is σ = 200003202330132. Its totient is φ = 200003202330130.
The previous prime is 200003202330119. The next prime is 200003202330133. The reversal of 200003202330131 is 131033202300002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200003202330131 - 210 = 200003202329107 is a prime.
It is a super-2 number, since 2×2000032023301312 (a number of 29 digits) contains 22 as substring.
Together with 200003202330133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (200003202330133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100001601165065 + 100001601165066.
It is an arithmetic number, because the mean of its divisors is an integer number (100001601165066).
Almost surely, 2200003202330131 is an apocalyptic number.
200003202330131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200003202330131 is an equidigital number, since it uses as much as digits as its factorization.
200003202330131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 200003202330131 its reverse (131033202300002), we get a palindrome (331036404630133).
The spelling of 200003202330131 in words is "two hundred trillion, three billion, two hundred two million, three hundred thirty thousand, one hundred thirty-one".
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