Base | Representation |
---|---|
bin | 10010101000000111… |
… | …100011110011001010 |
3 | 1220121212022202122122 |
4 | 102220013203303022 |
5 | 311430102014424 |
6 | 13104342251242 |
7 | 1305425535320 |
oct | 225007436312 |
9 | 56555282578 |
10 | 20000423114 |
11 | 8533798a01 |
12 | 3a62126b22 |
13 | 1b697c53b9 |
14 | d7a395d10 |
15 | 7c0d0145e |
hex | 4a81e3cca |
20000423114 has 32 divisors (see below), whose sum is σ = 34445938176. Its totient is φ = 8531832960.
The previous prime is 20000423089. The next prime is 20000423119. The reversal of 20000423114 is 41132400002.
It is a junction number, because it is equal to n+sod(n) for n = 20000423092 and 20000423101.
It is not an unprimeable number, because it can be changed into a prime (20000423119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2753912 + ... + 2761164.
It is an arithmetic number, because the mean of its divisors is an integer number (1076435568).
Almost surely, 220000423114 is an apocalyptic number.
20000423114 is a deficient number, since it is larger than the sum of its proper divisors (14445515062).
20000423114 is a wasteful number, since it uses less digits than its factorization.
20000423114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8150.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 20000423114 its reverse (41132400002), we get a palindrome (61132823116).
The spelling of 20000423114 in words is "twenty billion, four hundred twenty-three thousand, one hundred fourteen".
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