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200010011153 is a prime number
BaseRepresentation
bin1011101001000110000…
…1101001001000010001
3201010021001010022012212
42322101201221020101
511234110030324103
6231514444401505
720310302021021
oct2722141511021
9633231108185
10200010011153
1177907489787
123291ab46295
1315b26415b34
149975569a81
1553092a07d8
hex2e91869211

200010011153 has 2 divisors, whose sum is σ = 200010011154. Its totient is φ = 200010011152.

The previous prime is 200010011099. The next prime is 200010011183. The reversal of 200010011153 is 351110010002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199708884544 + 301126609 = 446888^2 + 17353^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200010011153 is a prime.

It is a super-2 number, since 2×2000100111532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (200010011183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005005576 + 100005005577.

It is an arithmetic number, because the mean of its divisors is an integer number (100005005577).

Almost surely, 2200010011153 is an apocalyptic number.

It is an amenable number.

200010011153 is a deficient number, since it is larger than the sum of its proper divisors (1).

200010011153 is an equidigital number, since it uses as much as digits as its factorization.

200010011153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

Adding to 200010011153 its reverse (351110010002), we get a palindrome (551120021155).

The spelling of 200010011153 in words is "two hundred billion, ten million, eleven thousand, one hundred fifty-three".