Base | Representation |
---|---|
bin | 1001000110000110110010… |
… | …01010110011111010100101 |
3 | 2121211002002212020210220021 |
4 | 10203003121022303322211 |
5 | 10110144032333021013 |
6 | 110312200540035141 |
7 | 4133011463163346 |
oct | 443033112637245 |
9 | 77732085223807 |
10 | 20001011220133 |
11 | 6411421454759 |
12 | 22b03b6232ab1 |
13 | b2111994bc48 |
14 | 4d20a868a0cd |
15 | 24a413a31a8d |
hex | 1230d92b3ea5 |
20001011220133 has 2 divisors, whose sum is σ = 20001011220134. Its totient is φ = 20001011220132.
The previous prime is 20001011220053. The next prime is 20001011220139. The reversal of 20001011220133 is 33102211010002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19610177442244 + 390833777889 = 4428338^2 + 625167^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20001011220133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20001011220139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000505610066 + 10000505610067.
It is an arithmetic number, because the mean of its divisors is an integer number (10000505610067).
Almost surely, 220001011220133 is an apocalyptic number.
It is an amenable number.
20001011220133 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001011220133 is an equidigital number, since it uses as much as digits as its factorization.
20001011220133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 20001011220133 its reverse (33102211010002), we get a palindrome (53103222230135).
The spelling of 20001011220133 in words is "twenty trillion, one billion, eleven million, two hundred twenty thousand, one hundred thirty-three".
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