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200011002012253 is a prime number
BaseRepresentation
bin101101011110100010110000…
…101110011110001001011101
3222020011212100121212012002201
4231132202300232132021131
5202203440013003343003
61545215441424451501
760062214041011135
oct5536426056361135
9866155317765081
10200011002012253
115880320a3a5a63
121a52357ba79b91
13877ac5873c3c3
143756826c99ac5
15181cb29dc9b1d
hexb5e8b0b9e25d

200011002012253 has 2 divisors, whose sum is σ = 200011002012254. Its totient is φ = 200011002012252.

The previous prime is 200011002012169. The next prime is 200011002012271. The reversal of 200011002012253 is 352210200110002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193544773489369 + 6466228522884 = 13912037^2 + 2542878^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200011002012253 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200011002012253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200011002012553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005501006126 + 100005501006127.

It is an arithmetic number, because the mean of its divisors is an integer number (100005501006127).

Almost surely, 2200011002012253 is an apocalyptic number.

It is an amenable number.

200011002012253 is a deficient number, since it is larger than the sum of its proper divisors (1).

200011002012253 is an equidigital number, since it uses as much as digits as its factorization.

200011002012253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 200011002012253 its reverse (352210200110002), we get a palindrome (552221202122255).

The spelling of 200011002012253 in words is "two hundred trillion, eleven billion, two million, twelve thousand, two hundred fifty-three".