Base | Representation |
---|---|
bin | 101101011110100010110001… |
… | …011000110011111000100010 |
3 | 222020011212101101202002011122 |
4 | 231132202301120303320202 |
5 | 202203440023324030310 |
6 | 1545215442502412242 |
7 | 60062214234236021 |
oct | 5536426130637042 |
9 | 866155341662148 |
10 | 200011013111330 |
11 | 58803215696953 |
12 | 1a523583731082 |
13 | 877ac5ab272c5 |
14 | 37568285488b8 |
15 | 181cb2ad6d555 |
hex | b5e8b1633e22 |
200011013111330 has 16 divisors (see below), whose sum is σ = 360190206896184. Its totient is φ = 79966542289920.
The previous prime is 200011013111219. The next prime is 200011013111447. The reversal of 200011013111330 is 33111310110002.
200011013111330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 84175065041809 + 115835948069521 = 9174697^2 + 10762711^2 .
It is a junction number, because it is equal to n+sod(n) for n = 200011013111299 and 200011013111308.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4732847141 + ... + 4732889400.
Almost surely, 2200011013111330 is an apocalyptic number.
200011013111330 is a deficient number, since it is larger than the sum of its proper divisors (160179193784854).
200011013111330 is a wasteful number, since it uses less digits than its factorization.
200011013111330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9465738661.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 200011013111330 its reverse (33111310110002), we get a palindrome (233122323221332).
The spelling of 200011013111330 in words is "two hundred trillion, eleven billion, thirteen million, one hundred eleven thousand, three hundred thirty".
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