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2000112143713 is a prime number
BaseRepresentation
bin11101000110101111111…
…110010100110101100001
321002012122020212100012221
4131012233332110311201
5230232212202044323
64130501104351041
7264334433465455
oct35065776246541
97065566770187
102000112143713
11701274187042
12283775615481
131167c086a3b8
146cb3d722665
1537062c8055d
hex1d1aff94d61

2000112143713 has 2 divisors, whose sum is σ = 2000112143714. Its totient is φ = 2000112143712.

The previous prime is 2000112143707. The next prime is 2000112143759. The reversal of 2000112143713 is 3173412110002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1671287885089 + 328824258624 = 1292783^2 + 573432^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000112143713 - 29 = 2000112143201 is a prime.

It is not a weakly prime, because it can be changed into another prime (2000112153713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000056071856 + 1000056071857.

It is an arithmetic number, because the mean of its divisors is an integer number (1000056071857).

Almost surely, 22000112143713 is an apocalyptic number.

It is an amenable number.

2000112143713 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000112143713 is an equidigital number, since it uses as much as digits as its factorization.

2000112143713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 2000112143713 its reverse (3173412110002), we get a palindrome (5173524253715).

The spelling of 2000112143713 in words is "two trillion, one hundred twelve million, one hundred forty-three thousand, seven hundred thirteen".