Base | Representation |
---|---|
bin | 11101000110101111111… |
… | …110010100110101100001 |
3 | 21002012122020212100012221 |
4 | 131012233332110311201 |
5 | 230232212202044323 |
6 | 4130501104351041 |
7 | 264334433465455 |
oct | 35065776246541 |
9 | 7065566770187 |
10 | 2000112143713 |
11 | 701274187042 |
12 | 283775615481 |
13 | 1167c086a3b8 |
14 | 6cb3d722665 |
15 | 37062c8055d |
hex | 1d1aff94d61 |
2000112143713 has 2 divisors, whose sum is σ = 2000112143714. Its totient is φ = 2000112143712.
The previous prime is 2000112143707. The next prime is 2000112143759. The reversal of 2000112143713 is 3173412110002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1671287885089 + 328824258624 = 1292783^2 + 573432^2 .
It is a cyclic number.
It is not a de Polignac number, because 2000112143713 - 29 = 2000112143201 is a prime.
It is not a weakly prime, because it can be changed into another prime (2000112153713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000056071856 + 1000056071857.
It is an arithmetic number, because the mean of its divisors is an integer number (1000056071857).
Almost surely, 22000112143713 is an apocalyptic number.
It is an amenable number.
2000112143713 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000112143713 is an equidigital number, since it uses as much as digits as its factorization.
2000112143713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2000112143713 its reverse (3173412110002), we get a palindrome (5173524253715).
The spelling of 2000112143713 in words is "two trillion, one hundred twelve million, one hundred forty-three thousand, seven hundred thirteen".
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