Base | Representation |
---|---|
bin | 11101000110101111111… |
… | …110010100111001001011 |
3 | 21002012122020212100112121 |
4 | 131012233332110321023 |
5 | 230232212202101242 |
6 | 4130501104352111 |
7 | 264334433466241 |
oct | 35065776247113 |
9 | 7065566770477 |
10 | 2000112143947 |
11 | 701274187235 |
12 | 283775615637 |
13 | 1167c086a538 |
14 | 6cb3d722791 |
15 | 37062c80667 |
hex | 1d1aff94e4b |
2000112143947 has 2 divisors, whose sum is σ = 2000112143948. Its totient is φ = 2000112143946.
The previous prime is 2000112143941. The next prime is 2000112143969. The reversal of 2000112143947 is 7493412110002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2000112143947 - 211 = 2000112141899 is a prime.
It is a super-3 number, since 3×20001121439473 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2000112143941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000056071973 + 1000056071974.
It is an arithmetic number, because the mean of its divisors is an integer number (1000056071974).
Almost surely, 22000112143947 is an apocalyptic number.
2000112143947 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000112143947 is an equidigital number, since it uses as much as digits as its factorization.
2000112143947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 34.
Adding to 2000112143947 its reverse (7493412110002), we get a palindrome (9493524253949).
The spelling of 2000112143947 in words is "two trillion, one hundred twelve million, one hundred forty-three thousand, nine hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •