Search a number
-
+
20001131053 is a prime number
BaseRepresentation
bin10010101000001010…
…010000101000101101
31220121220122201202121
4102220022100220231
5311430242143203
613104405352541
71305434544301
oct225012205055
956556581677
1020001131053
118534131882
123a62408751
131b699b26b7
14d7a4dbd01
157c0de10bd
hex4a8290a2d

20001131053 has 2 divisors, whose sum is σ = 20001131054. Its totient is φ = 20001131052.

The previous prime is 20001131021. The next prime is 20001131173. The reversal of 20001131053 is 35013110002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15276218409 + 4724912644 = 123597^2 + 68738^2 .

It is a cyclic number.

It is not a de Polignac number, because 20001131053 - 25 = 20001131021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20001135053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000565526 + 10000565527.

It is an arithmetic number, because the mean of its divisors is an integer number (10000565527).

Almost surely, 220001131053 is an apocalyptic number.

It is an amenable number.

20001131053 is a deficient number, since it is larger than the sum of its proper divisors (1).

20001131053 is an equidigital number, since it uses as much as digits as its factorization.

20001131053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 16.

Adding to 20001131053 its reverse (35013110002), we get a palindrome (55014241055).

The spelling of 20001131053 in words is "twenty billion, one million, one hundred thirty-one thousand, fifty-three".