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200011321230983 is a prime number
BaseRepresentation
bin101101011110100011000011…
…110000001100011010000111
3222020011220011212112011212122
4231132203003300030122013
5202203441141213342413
61545215533230440155
760062224665224033
oct5536430360143207
9866156155464778
10200011321230983
1158803363606799
121a52364a96305b
13877aca9908b22
1437568574331c3
15181cb47e33108
hexb5e8c3c0c687

200011321230983 has 2 divisors, whose sum is σ = 200011321230984. Its totient is φ = 200011321230982.

The previous prime is 200011321230967. The next prime is 200011321231067. The reversal of 200011321230983 is 389032123110002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200011321230983 - 24 = 200011321230967 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200011321230953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005660615491 + 100005660615492.

It is an arithmetic number, because the mean of its divisors is an integer number (100005660615492).

Almost surely, 2200011321230983 is an apocalyptic number.

200011321230983 is a deficient number, since it is larger than the sum of its proper divisors (1).

200011321230983 is an equidigital number, since it uses as much as digits as its factorization.

200011321230983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

Adding to 200011321230983 its reverse (389032123110002), we get a palindrome (589043444340985).

The spelling of 200011321230983 in words is "two hundred trillion, eleven billion, three hundred twenty-one million, two hundred thirty thousand, nine hundred eighty-three".