Base | Representation |
---|---|
bin | 11101000110110000011… |
… | …100010111110000001111 |
3 | 21002012122210200111102122 |
4 | 131012300130113300033 |
5 | 230232221211114413 |
6 | 4130501545243155 |
7 | 264334560441401 |
oct | 35066034276017 |
9 | 7065583614378 |
10 | 2000120019983 |
11 | 701278676658 |
12 | 2837781934bb |
13 | 1167c2397407 |
14 | 6cb407b2b71 |
15 | 370637d9108 |
hex | 1d1b0717c0f |
2000120019983 has 2 divisors, whose sum is σ = 2000120019984. Its totient is φ = 2000120019982.
The previous prime is 2000120019979. The next prime is 2000120020039. The reversal of 2000120019983 is 3899100210002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2000120019983 - 22 = 2000120019979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2000120019913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000060009991 + 1000060009992.
It is an arithmetic number, because the mean of its divisors is an integer number (1000060009992).
Almost surely, 22000120019983 is an apocalyptic number.
2000120019983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000120019983 is an equidigital number, since it uses as much as digits as its factorization.
2000120019983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 35.
Adding to 2000120019983 its reverse (3899100210002), we get a palindrome (5899220229985).
The spelling of 2000120019983 in words is "two trillion, one hundred twenty million, nineteen thousand, nine hundred eighty-three".
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