Base | Representation |
---|---|
bin | 1001000110000111001011… |
… | …00111101000010000001011 |
3 | 2121211002122102022001202112 |
4 | 10203003211213220100023 |
5 | 10110144444321214011 |
6 | 110312233401052535 |
7 | 4133016610510013 |
oct | 443034547502013 |
9 | 77732572261675 |
10 | 20001220101131 |
11 | 6411519353085 |
12 | 22b045418714b |
13 | b21150cc5679 |
14 | 4d20c8300c43 |
15 | 24a42704258b |
hex | 1230e59e840b |
20001220101131 has 2 divisors, whose sum is σ = 20001220101132. Its totient is φ = 20001220101130.
The previous prime is 20001220101001. The next prime is 20001220101169. The reversal of 20001220101131 is 13110102210002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20001220101131 - 238 = 19726342194187 is a prime.
It is a super-3 number, since 3×200012201011313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (20001220101431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000610050565 + 10000610050566.
It is an arithmetic number, because the mean of its divisors is an integer number (10000610050566).
Almost surely, 220001220101131 is an apocalyptic number.
20001220101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001220101131 is an equidigital number, since it uses as much as digits as its factorization.
20001220101131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 20001220101131 its reverse (13110102210002), we get a palindrome (33111322311133).
The spelling of 20001220101131 in words is "twenty trillion, one billion, two hundred twenty million, one hundred one thousand, one hundred thirty-one".
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