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2000122120193 is a prime number
BaseRepresentation
bin11101000110110000100…
…100011000100000000001
321002012122221122012101012
4131012300210120200001
5230232222230321233
64130502102250305
7264334614336431
oct35066044304001
97065587565335
102000122120193
1170127988056a
12283778a26995
131167c2951342
146cb40b9c2c1
1537063aa1548
hex1d1b0918801

2000122120193 has 2 divisors, whose sum is σ = 2000122120194. Its totient is φ = 2000122120192.

The previous prime is 2000122120133. The next prime is 2000122120277. The reversal of 2000122120193 is 3910212210002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1738895843584 + 261226276609 = 1318672^2 + 511103^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000122120193 - 28 = 2000122119937 is a prime.

It is not a weakly prime, because it can be changed into another prime (2000122120123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000061060096 + 1000061060097.

It is an arithmetic number, because the mean of its divisors is an integer number (1000061060097).

Almost surely, 22000122120193 is an apocalyptic number.

It is an amenable number.

2000122120193 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000122120193 is an equidigital number, since it uses as much as digits as its factorization.

2000122120193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 2000122120193 its reverse (3910212210002), we get a palindrome (5910334330195).

The spelling of 2000122120193 in words is "two trillion, one hundred twenty-two million, one hundred twenty thousand, one hundred ninety-three".