Base | Representation |
---|---|
bin | 10010101000001010… |
… | …101011100100110111 |
3 | 1220121220212100010111 |
4 | 102220022223210313 |
5 | 311430304211044 |
6 | 13104412003451 |
7 | 1305435514066 |
oct | 225012534467 |
9 | 56556770114 |
10 | 20001241399 |
11 | 85341a7777 |
12 | 3a62460587 |
13 | 1b69a209a9 |
14 | d7a52a1dd |
15 | 7c0e13b34 |
hex | 4a82ab937 |
20001241399 has 2 divisors, whose sum is σ = 20001241400. Its totient is φ = 20001241398.
The previous prime is 20001241373. The next prime is 20001241411. The reversal of 20001241399 is 99314210002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20001241399 - 211 = 20001239351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20001241399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20001242399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000620699 + 10000620700.
It is an arithmetic number, because the mean of its divisors is an integer number (10000620700).
Almost surely, 220001241399 is an apocalyptic number.
20001241399 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001241399 is an equidigital number, since it uses as much as digits as its factorization.
20001241399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 20001241399 in words is "twenty billion, one million, two hundred forty-one thousand, three hundred ninety-nine".
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