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200020110110131 is a prime number
BaseRepresentation
bin101101011110101011001111…
…100111000110110110110011
3222020012201212101100111112011
4231132223033213012312303
5202204112141142011011
61545223545310543351
760062655535402303
oct5536531747066663
9866181771314464
10200020110110131
1158807063709783
121a5252a2207b57
13877ba7a70a02c
14375704c7ad603
15181ceae80a621
hexb5eacf9c6db3

200020110110131 has 2 divisors, whose sum is σ = 200020110110132. Its totient is φ = 200020110110130.

The previous prime is 200020110110089. The next prime is 200020110110203. The reversal of 200020110110131 is 131011011020002.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200020110110131 - 29 = 200020110109619 is a prime.

It is a super-2 number, since 2×2000201101101312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (200020110110531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100010055055065 + 100010055055066.

It is an arithmetic number, because the mean of its divisors is an integer number (100010055055066).

Almost surely, 2200020110110131 is an apocalyptic number.

200020110110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

200020110110131 is an equidigital number, since it uses as much as digits as its factorization.

200020110110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 200020110110131 its reverse (131011011020002), we get a palindrome (331031121130133).

The spelling of 200020110110131 in words is "two hundred trillion, twenty billion, one hundred ten million, one hundred ten thousand, one hundred thirty-one".