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20002100012113 is a prime number
BaseRepresentation
bin1001000110001000110100…
…00100001110010001010001
32121211011220202000011201011
410203010122010032101101
510110203300100341423
6110312500552410521
74133050453566112
oct443043204162121
977734822004634
1020002100012113
11641193000423a
1222b065a9a6a41
13b212613a725b
144d216d10c209
1524a479401b0d
hex12311a10e451

20002100012113 has 2 divisors, whose sum is σ = 20002100012114. Its totient is φ = 20002100012112.

The previous prime is 20002100012099. The next prime is 20002100012179. The reversal of 20002100012113 is 31121000120002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13904598258769 + 6097501753344 = 3728887^2 + 2469312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20002100012113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20002100012093 and 20002100012102.

It is not a weakly prime, because it can be changed into another prime (20002100012413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001050006056 + 10001050006057.

It is an arithmetic number, because the mean of its divisors is an integer number (10001050006057).

Almost surely, 220002100012113 is an apocalyptic number.

It is an amenable number.

20002100012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20002100012113 is an equidigital number, since it uses as much as digits as its factorization.

20002100012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20002100012113 its reverse (31121000120002), we get a palindrome (51123100132115).

The spelling of 20002100012113 in words is "twenty trillion, two billion, one hundred million, twelve thousand, one hundred thirteen".