Base | Representation |
---|---|
bin | 11101000110110101111… |
… | …100000000111010001111 |
3 | 21002012220020010210011012 |
4 | 131012311330000322033 |
5 | 230232413310413403 |
6 | 4130515041115435 |
7 | 264340060120124 |
oct | 35066574007217 |
9 | 7065806123135 |
10 | 2000212201103 |
11 | 7013157076a6 |
12 | 2837a3028b7b |
13 | 11680850105c |
14 | 6cb4cb2a74b |
15 | 3706b946ed8 |
hex | 1d1b5f00e8f |
2000212201103 has 16 divisors (see below), whose sum is σ = 2093225172480. Its totient is φ = 1909256184576.
The previous prime is 2000212201061. The next prime is 2000212201121. The reversal of 2000212201103 is 3011022120002.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 2000212201103 - 210 = 2000212200079 is a prime.
It is a super-2 number, since 2×20002122011032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2000212201193) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24430451 + ... + 24512187.
It is an arithmetic number, because the mean of its divisors is an integer number (130826573280).
Almost surely, 22000212201103 is an apocalyptic number.
2000212201103 is a deficient number, since it is larger than the sum of its proper divisors (93012971377).
2000212201103 is a wasteful number, since it uses less digits than its factorization.
2000212201103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94306.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 2000212201103 its reverse (3011022120002), we get a palindrome (5011234321105).
The spelling of 2000212201103 in words is "two trillion, two hundred twelve million, two hundred one thousand, one hundred three".
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