Base | Representation |
---|---|
bin | 1001000110001001000000… |
… | …00110010000110100100111 |
3 | 2121211012011210102120022122 |
4 | 10203010200012100310213 |
5 | 10110204002002211101 |
6 | 110312515005420155 |
7 | 4133053123011116 |
oct | 443044006206447 |
9 | 77735153376278 |
10 | 20002201210151 |
11 | 6411982143886 |
12 | 22b068886a65b |
13 | b2127934a154 |
14 | 4d217c731c7d |
15 | 24a48324151b |
hex | 123120190d27 |
20002201210151 has 2 divisors, whose sum is σ = 20002201210152. Its totient is φ = 20002201210150.
The previous prime is 20002201210093. The next prime is 20002201210157. The reversal of 20002201210151 is 15101210220002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20002201210151 - 222 = 20002197015847 is a prime.
It is a super-2 number, since 2×200022012101512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20002201210157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001100605075 + 10001100605076.
It is an arithmetic number, because the mean of its divisors is an integer number (10001100605076).
Almost surely, 220002201210151 is an apocalyptic number.
20002201210151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20002201210151 is an equidigital number, since it uses as much as digits as its factorization.
20002201210151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 20002201210151 its reverse (15101210220002), we get a palindrome (35103411430153).
The spelling of 20002201210151 in words is "twenty trillion, two billion, two hundred one million, two hundred ten thousand, one hundred fifty-one".
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