20002201221113 has 2 divisors, whose sum is σ = 20002201221114. Its totient is φ = 20002201221112.

The previous prime is 20002201220993. The next prime is 20002201221131. The reversal of 20002201221113 is 31112210220002.

Together with next prime (20002201221131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15045112712809 + 4957088508304 = 3878803^2 + 2226452^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20002201221113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20002201221091 and 20002201221100.

It is not a weakly prime, because it can be changed into another prime (20002201221133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001100610556 + 10001100610557.

It is an arithmetic number, because the mean of its divisors is an integer number (10001100610557).

Almost surely, 2^{20002201221113} is an apocalyptic number.

It is an amenable number.

20002201221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20002201221113 is an equidigital number, since it uses as much as digits as its factorization.

20002201221113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20002201221113 its reverse (31112210220002), we get a palindrome (51114411441115).

The spelling of 20002201221113 in words is "twenty trillion, two billion, two hundred one million, two hundred twenty-one thousand, one hundred thirteen".