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2000310112117 is a prime number
BaseRepresentation
bin11101000110111011110…
…001100000111101110101
321002020011001101011211001
4131012323301200331311
5230233113342041432
64130532455443301
7264342356262022
oct35067361407565
97066131334731
102000310112117
11701365a01699
1228380b986531
13116822892a75
146cb5bb36549
15370753379e7
hex1d1bbc60f75

2000310112117 has 2 divisors, whose sum is σ = 2000310112118. Its totient is φ = 2000310112116.

The previous prime is 2000310112091. The next prime is 2000310112133. The reversal of 2000310112117 is 7112110130002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1146079443601 + 854230668516 = 1070551^2 + 924246^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2000310112117 is a prime.

It is a super-2 number, since 2×20003101121172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2000310112094 and 2000310112103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2000310112817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000155056058 + 1000155056059.

It is an arithmetic number, because the mean of its divisors is an integer number (1000155056059).

Almost surely, 22000310112117 is an apocalyptic number.

It is an amenable number.

2000310112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000310112117 is an equidigital number, since it uses as much as digits as its factorization.

2000310112117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 2000310112117 its reverse (7112110130002), we get a palindrome (9112420242119).

The spelling of 2000310112117 in words is "two trillion, three hundred ten million, one hundred twelve thousand, one hundred seventeen".