Base | Representation |
---|---|
bin | 1001000110001011010001… |
… | …10111010000011011110101 |
3 | 2121211022022212120210020101 |
4 | 10203011220313100123311 |
5 | 10110214002013410143 |
6 | 110313240055434101 |
7 | 4133125305451444 |
oct | 443055067203365 |
9 | 77738285523211 |
10 | 20003422013173 |
11 | 64124492691a5 |
12 | 22b0969685931 |
13 | b214122463c1 |
14 | 4d2256918d5b |
15 | 24a5054dab4d |
hex | 123168dd06f5 |
20003422013173 has 2 divisors, whose sum is σ = 20003422013174. Its totient is φ = 20003422013172.
The previous prime is 20003422013161. The next prime is 20003422013177. The reversal of 20003422013173 is 37131022430002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13247285061124 + 6756136952049 = 3639682^2 + 2599257^2 .
It is a cyclic number.
It is not a de Polignac number, because 20003422013173 - 225 = 20003388458741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20003422013177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001711006586 + 10001711006587.
It is an arithmetic number, because the mean of its divisors is an integer number (10001711006587).
Almost surely, 220003422013173 is an apocalyptic number.
It is an amenable number.
20003422013173 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003422013173 is an equidigital number, since it uses as much as digits as its factorization.
20003422013173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 20003422013173 its reverse (37131022430002), we get a palindrome (57134444443175).
The spelling of 20003422013173 in words is "twenty trillion, three billion, four hundred twenty-two million, thirteen thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •