Base | Representation |
---|---|
bin | 1001000110001011011100… |
… | …10010111110011110010101 |
3 | 2121211022120020002211000112 |
4 | 10203011232102332132111 |
5 | 10110214143332300332 |
6 | 110313253113252405 |
7 | 4133130463314344 |
oct | 443055622763625 |
9 | 77738506084015 |
10 | 20003513165717 |
11 | 6412495767484 |
12 | 22b0994104105 |
13 | b214280acb13 |
14 | 4d2264a85b5b |
15 | 24a50d4e3db2 |
hex | 12316e4be795 |
20003513165717 has 2 divisors, whose sum is σ = 20003513165718. Its totient is φ = 20003513165716.
The previous prime is 20003513165707. The next prime is 20003513165773. The reversal of 20003513165717 is 71756131530002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12182619910321 + 7820893255396 = 3490361^2 + 2796586^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20003513165717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20003513165707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001756582858 + 10001756582859.
It is an arithmetic number, because the mean of its divisors is an integer number (10001756582859).
Almost surely, 220003513165717 is an apocalyptic number.
It is an amenable number.
20003513165717 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003513165717 is an equidigital number, since it uses as much as digits as its factorization.
20003513165717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 132300, while the sum is 41.
Adding to 20003513165717 its reverse (71756131530002), we get a palindrome (91759644695719).
The spelling of 20003513165717 in words is "twenty trillion, three billion, five hundred thirteen million, one hundred sixty-five thousand, seven hundred seventeen".
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