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20003555414681 is a prime number
BaseRepresentation
bin1001000110001011100001…
…10100001001001010011001
32121211022200011121021200222
410203011300310021022121
510110214240141232211
6110313301223005425
74133131515400226
oct443056064111231
977738604537628
1020003555414681
1164125075a3783
1222b09a6299875
13b21433a831c7
144d226a52294d
1524a51208c1db
hex123170d09299

20003555414681 has 2 divisors, whose sum is σ = 20003555414682. Its totient is φ = 20003555414680.

The previous prime is 20003555414587. The next prime is 20003555414683. The reversal of 20003555414681 is 18641455530002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19783894472281 + 219660942400 = 4447909^2 + 468680^2 .

It is a cyclic number.

It is not a de Polignac number, because 20003555414681 - 226 = 20003488305817 is a prime.

It is a super-4 number, since 4×200035554146814 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 20003555414683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20003555414683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001777707340 + 10001777707341.

It is an arithmetic number, because the mean of its divisors is an integer number (10001777707341).

Almost surely, 220003555414681 is an apocalyptic number.

It is an amenable number.

20003555414681 is a deficient number, since it is larger than the sum of its proper divisors (1).

20003555414681 is an equidigital number, since it uses as much as digits as its factorization.

20003555414681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576000, while the sum is 44.

The spelling of 20003555414681 in words is "twenty trillion, three billion, five hundred fifty-five million, four hundred fourteen thousand, six hundred eighty-one".