Base | Representation |
---|---|
bin | 10010101000010110… |
… | …000011110001101111 |
3 | 1220122010110212122022 |
4 | 102220112003301233 |
5 | 311432040132421 |
6 | 13104555540355 |
7 | 1305503046044 |
oct | 225026036157 |
9 | 56563425568 |
10 | 20004224111 |
11 | 8535954723 |
12 | 3a6345a6bb |
13 | 1b6a526501 |
14 | d7aaa51cb |
15 | 7c13027ab |
hex | 4a8583c6f |
20004224111 has 2 divisors, whose sum is σ = 20004224112. Its totient is φ = 20004224110.
The previous prime is 20004224089. The next prime is 20004224117. The reversal of 20004224111 is 11142240002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20004224111 - 26 = 20004224047 is a prime.
It is a super-2 number, since 2×200042241112 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20004224111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20004224117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002112055 + 10002112056.
It is an arithmetic number, because the mean of its divisors is an integer number (10002112056).
Almost surely, 220004224111 is an apocalyptic number.
20004224111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20004224111 is an equidigital number, since it uses as much as digits as its factorization.
20004224111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 128, while the sum is 17.
Adding to 20004224111 its reverse (11142240002), we get a palindrome (31146464113).
The spelling of 20004224111 in words is "twenty billion, four million, two hundred twenty-four thousand, one hundred eleven".
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