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20004304356557 is a prime number
BaseRepresentation
bin1001000110001100111010…
…11101001000010011001101
32121211101121100212110210222
410203012131131020103031
510110222303403402212
6110313503415241125
74133156211321233
oct443063535102315
977741540773728
1020004304356557
116412861330904
1222b0b750791a5
13b21522c9a191
144d22dbb9a953
1524a557bcac72
hex12319d7484cd

20004304356557 has 2 divisors, whose sum is σ = 20004304356558. Its totient is φ = 20004304356556.

The previous prime is 20004304356503. The next prime is 20004304356607. The reversal of 20004304356557 is 75565340340002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10095495830281 + 9908808526276 = 3177341^2 + 3147826^2 .

It is a cyclic number.

It is not a de Polignac number, because 20004304356557 - 216 = 20004304291021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20004304356457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002152178278 + 10002152178279.

It is an arithmetic number, because the mean of its divisors is an integer number (10002152178279).

Almost surely, 220004304356557 is an apocalyptic number.

It is an amenable number.

20004304356557 is a deficient number, since it is larger than the sum of its proper divisors (1).

20004304356557 is an equidigital number, since it uses as much as digits as its factorization.

20004304356557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 44.

Adding to 20004304356557 its reverse (75565340340002), we get a palindrome (95569644696559).

The spelling of 20004304356557 in words is "twenty trillion, four billion, three hundred four million, three hundred fifty-six thousand, five hundred fifty-seven".