Base | Representation |
---|---|
bin | 1001000110001101000001… |
… | …00011011111100110011011 |
3 | 2121211101201222201100100001 |
4 | 10203012200203133212123 |
5 | 10110222410211402012 |
6 | 110313512513553431 |
7 | 4133160412315465 |
oct | 443064043374633 |
9 | 77741658640301 |
10 | 20004356356507 |
11 | 6412888718176 |
12 | 22b0b8a575877 |
13 | b215309a5993 |
14 | 4d2304a55135 |
15 | 24a55c54d357 |
hex | 1231a08df99b |
20004356356507 has 2 divisors, whose sum is σ = 20004356356508. Its totient is φ = 20004356356506.
The previous prime is 20004356356493. The next prime is 20004356356553. The reversal of 20004356356507 is 70565365340002.
It is an a-pointer prime, because the next prime (20004356356553) can be obtained adding 20004356356507 to its sum of digits (46).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20004356356507 - 215 = 20004356323739 is a prime.
It is a super-3 number, since 3×200043563565073 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (20004356356307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002178178253 + 10002178178254.
It is an arithmetic number, because the mean of its divisors is an integer number (10002178178254).
Almost surely, 220004356356507 is an apocalyptic number.
20004356356507 is a deficient number, since it is larger than the sum of its proper divisors (1).
20004356356507 is an equidigital number, since it uses as much as digits as its factorization.
20004356356507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268000, while the sum is 46.
The spelling of 20004356356507 in words is "twenty trillion, four billion, three hundred fifty-six million, three hundred fifty-six thousand, five hundred seven".
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