Base | Representation |
---|---|
bin | 1001000110001110011011… |
… | …01111100110000101110101 |
3 | 2121211110200211022012112211 |
4 | 10203013031233212011311 |
5 | 10110230433303103131 |
6 | 110314120035413421 |
7 | 4133215246415626 |
oct | 443071557460565 |
9 | 77743624265484 |
10 | 20005114503541 |
11 | 6413137672272 |
12 | 22b1160454271 |
13 | b21621a937ab |
14 | 4d2377607a4d |
15 | 24a5a3da95b1 |
hex | 1231cdbe6175 |
20005114503541 has 2 divisors, whose sum is σ = 20005114503542. Its totient is φ = 20005114503540.
The previous prime is 20005114503503. The next prime is 20005114503551. The reversal of 20005114503541 is 14530541150002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12455753791441 + 7549360712100 = 3529271^2 + 2747610^2 .
It is a cyclic number.
It is not a de Polignac number, because 20005114503541 - 213 = 20005114495349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20005114503551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002557251770 + 10002557251771.
It is an arithmetic number, because the mean of its divisors is an integer number (10002557251771).
Almost surely, 220005114503541 is an apocalyptic number.
It is an amenable number.
20005114503541 is a deficient number, since it is larger than the sum of its proper divisors (1).
20005114503541 is an equidigital number, since it uses as much as digits as its factorization.
20005114503541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 20005114503541 its reverse (14530541150002), we get a palindrome (34535655653543).
The spelling of 20005114503541 in words is "twenty trillion, five billion, one hundred fourteen million, five hundred three thousand, five hundred forty-one".
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