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200102113 is a prime number
BaseRepresentation
bin10111110110101…
…01000011100001
3111221112020111101
423323111003201
5402211231423
631504514401
74646561041
oct1373250341
9457466441
10200102113
11a2a52752
125701ba01
13325c1923
141c80b721
15128797ad
hexbed50e1

200102113 has 2 divisors, whose sum is σ = 200102114. Its totient is φ = 200102112.

The previous prime is 200102101. The next prime is 200102153. The reversal of 200102113 is 311201002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199572129 + 529984 = 14127^2 + 728^2 .

It is a cyclic number.

It is not a de Polignac number, because 200102113 - 225 = 166547681 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200102113.

It is not a weakly prime, because it can be changed into another prime (200102153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100051056 + 100051057.

It is an arithmetic number, because the mean of its divisors is an integer number (100051057).

Almost surely, 2200102113 is an apocalyptic number.

It is an amenable number.

200102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200102113 is an equidigital number, since it uses as much as digits as its factorization.

200102113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 200102113 is about 14145.7454027704. The cubic root of 200102113 is about 584.9030574502.

Adding to 200102113 its reverse (311201002), we get a palindrome (511303115).

The spelling of 200102113 in words is "two hundred million, one hundred two thousand, one hundred thirteen".