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2001110011141 is a prime number
BaseRepresentation
bin11101000111101011011…
…100111000110100000101
321002022012210112020222211
4131013223130320310011
5230241233130324031
64131144112223421
7264401241305113
oct35075334706405
97068183466884
102001110011141
1170173648366a
122839b383ab71
1311691c50b9b7
146cbd6076ab3
15370c068ebb1
hex1d1eb738d05

2001110011141 has 2 divisors, whose sum is σ = 2001110011142. Its totient is φ = 2001110011140.

The previous prime is 2001110011091. The next prime is 2001110011151. The reversal of 2001110011141 is 1411100111002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1380566250625 + 620543760516 = 1174975^2 + 787746^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001110011141 - 221 = 2001107913989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001110011151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000555005570 + 1000555005571.

It is an arithmetic number, because the mean of its divisors is an integer number (1000555005571).

Almost surely, 22001110011141 is an apocalyptic number.

It is an amenable number.

2001110011141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001110011141 is an equidigital number, since it uses as much as digits as its factorization.

2001110011141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 2001110011141 its reverse (1411100111002), we get a palindrome (3412210122143).

The spelling of 2001110011141 in words is "two trillion, one billion, one hundred ten million, eleven thousand, one hundred forty-one".