Base | Representation |
---|---|
bin | 1001000110011001100101… |
… | …01000001000001011110011 |
3 | 2121212001011002212011020211 |
4 | 10203030302220020023303 |
5 | 10110330214103342042 |
6 | 110320550124444551 |
7 | 4133516522410141 |
oct | 443146250101363 |
9 | 77761132764224 |
10 | 20011102012147 |
11 | 641572a441094 |
12 | 22b23516a9757 |
13 | b220673a79ac |
14 | 4d27848c4591 |
15 | 24a804876017 |
hex | 123332a082f3 |
20011102012147 has 2 divisors, whose sum is σ = 20011102012148. Its totient is φ = 20011102012146.
The previous prime is 20011102012091. The next prime is 20011102012177. The reversal of 20011102012147 is 74121020111002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20011102012147 - 211 = 20011102010099 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011102012177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005551006073 + 10005551006074.
It is an arithmetic number, because the mean of its divisors is an integer number (10005551006074).
Almost surely, 220011102012147 is an apocalyptic number.
20011102012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011102012147 is an equidigital number, since it uses as much as digits as its factorization.
20011102012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 20011102012147 its reverse (74121020111002), we get a palindrome (94132122123149).
The spelling of 20011102012147 in words is "twenty trillion, eleven billion, one hundred two million, twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •