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20011111200203 is a prime number
BaseRepresentation
bin1001000110011001100110…
…01011001011010111001011
32121212001011202010221220012
410203030303023023113023
510110330223431401303
6110320551053422135
74133516663455364
oct443146313132713
977761152127805
1020011111200203
116415734647222
1222b235479a94b
13b22069273b06
144d2785bd6b6b
1524a80558d5d8
hex1233332cb5cb

20011111200203 has 2 divisors, whose sum is σ = 20011111200204. Its totient is φ = 20011111200202.

The previous prime is 20011111200161. The next prime is 20011111200229. The reversal of 20011111200203 is 30200211111002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20011111200203 - 216 = 20011111134667 is a prime.

It is a super-3 number, since 3×200111112002033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20011111209203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005555600101 + 10005555600102.

It is an arithmetic number, because the mean of its divisors is an integer number (10005555600102).

Almost surely, 220011111200203 is an apocalyptic number.

20011111200203 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011111200203 is an equidigital number, since it uses as much as digits as its factorization.

20011111200203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 20011111200203 its reverse (30200211111002), we get a palindrome (50211322311205).

The spelling of 20011111200203 in words is "twenty trillion, eleven billion, one hundred eleven million, two hundred thousand, two hundred three".