Base | Representation |
---|---|
bin | 1001000110011001100110… |
… | …01011001011010111001011 |
3 | 2121212001011202010221220012 |
4 | 10203030303023023113023 |
5 | 10110330223431401303 |
6 | 110320551053422135 |
7 | 4133516663455364 |
oct | 443146313132713 |
9 | 77761152127805 |
10 | 20011111200203 |
11 | 6415734647222 |
12 | 22b235479a94b |
13 | b22069273b06 |
14 | 4d2785bd6b6b |
15 | 24a80558d5d8 |
hex | 1233332cb5cb |
20011111200203 has 2 divisors, whose sum is σ = 20011111200204. Its totient is φ = 20011111200202.
The previous prime is 20011111200161. The next prime is 20011111200229. The reversal of 20011111200203 is 30200211111002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20011111200203 - 216 = 20011111134667 is a prime.
It is a super-3 number, since 3×200111112002033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (20011111209203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005555600101 + 10005555600102.
It is an arithmetic number, because the mean of its divisors is an integer number (10005555600102).
Almost surely, 220011111200203 is an apocalyptic number.
20011111200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011111200203 is an equidigital number, since it uses as much as digits as its factorization.
20011111200203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 20011111200203 its reverse (30200211111002), we get a palindrome (50211322311205).
The spelling of 20011111200203 in words is "twenty trillion, eleven billion, one hundred eleven million, two hundred thousand, two hundred three".
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