Base | Representation |
---|---|
bin | 101101100000000000001100… |
… | …111100000101100001000001 |
3 | 222020112110022212221101001022 |
4 | 231200000030330011201001 |
5 | 202212111002313124212 |
6 | 1545333513305115225 |
7 | 60102365250115406 |
oct | 5540001474054101 |
9 | 866473285841038 |
10 | 200111333333057 |
11 | 58841815858303 |
12 | 1a53ab00788b15 |
13 | 8787557a94b53 |
14 | 375b623d242ad |
15 | 182054d25d772 |
hex | b6000cf05841 |
200111333333057 has 2 divisors, whose sum is σ = 200111333333058. Its totient is φ = 200111333333056.
The previous prime is 200111333333029. The next prime is 200111333333071. The reversal of 200111333333057 is 750333333111002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134698678912576 + 65412654420481 = 11605976^2 + 8087809^2 .
It is a cyclic number.
It is not a de Polignac number, because 200111333333057 - 236 = 200042613856321 is a prime.
It is not a weakly prime, because it can be changed into another prime (200111333338057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055666666528 + 100055666666529.
It is an arithmetic number, because the mean of its divisors is an integer number (100055666666529).
Almost surely, 2200111333333057 is an apocalyptic number.
It is an amenable number.
200111333333057 is a deficient number, since it is larger than the sum of its proper divisors (1).
200111333333057 is an equidigital number, since it uses as much as digits as its factorization.
200111333333057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51030, while the sum is 35.
Adding to 200111333333057 its reverse (750333333111002), we get a palindrome (950444666444059).
The spelling of 200111333333057 in words is "two hundred trillion, one hundred eleven billion, three hundred thirty-three million, three hundred thirty-three thousand, fifty-seven".
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