Base | Representation |
---|---|
bin | 11101000111101100000… |
… | …010111111100001110111 |
3 | 21002022020111022202021222 |
4 | 131013230002333201313 |
5 | 230241243210000434 |
6 | 4131145110300555 |
7 | 264401422230362 |
oct | 35075402774167 |
9 | 7068214282258 |
10 | 2001120000119 |
11 | 701741086519 |
12 | 2839b705775b |
13 | 1169215c8536 |
14 | 6cbd75170d9 |
15 | 370c14b472e |
hex | 1d1ec0bf877 |
2001120000119 has 2 divisors, whose sum is σ = 2001120000120. Its totient is φ = 2001120000118.
The previous prime is 2001120000101. The next prime is 2001120000133. The reversal of 2001120000119 is 9110000211002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001120000119 is a prime.
It is a super-2 number, since 2×20011200001192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001120000097 and 2001120000106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001120000199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000560000059 + 1000560000060.
It is an arithmetic number, because the mean of its divisors is an integer number (1000560000060).
Almost surely, 22001120000119 is an apocalyptic number.
2001120000119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001120000119 is an equidigital number, since it uses as much as digits as its factorization.
2001120000119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
The spelling of 2001120000119 in words is "two trillion, one billion, one hundred twenty million, one hundred nineteen", and thus it is an aban number.
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