Base | Representation |
---|---|
bin | 101101100000000000111011… |
… | …001111010000011000100111 |
3 | 222020112112100000120202000212 |
4 | 231200000323033100120213 |
5 | 202212114100142011442 |
6 | 1545334122334130035 |
7 | 60102423431451056 |
oct | 5540007317203047 |
9 | 866475300522025 |
10 | 200112110110247 |
11 | 58842084277525 |
12 | 1a53b09895091b |
13 | 878764c9a671a |
14 | 375b69916639d |
15 | 1820596549a82 |
hex | b6003b3d0627 |
200112110110247 has 2 divisors, whose sum is σ = 200112110110248. Its totient is φ = 200112110110246.
The previous prime is 200112110110219. The next prime is 200112110110321. The reversal of 200112110110247 is 742011011211002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200112110110247 - 218 = 200112109848103 is a prime.
It is a super-2 number, since 2×2001121101102472 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200112110112247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056055055123 + 100056055055124.
It is an arithmetic number, because the mean of its divisors is an integer number (100056055055124).
Almost surely, 2200112110110247 is an apocalyptic number.
200112110110247 is a deficient number, since it is larger than the sum of its proper divisors (1).
200112110110247 is an equidigital number, since it uses as much as digits as its factorization.
200112110110247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 200112110110247 its reverse (742011011211002), we get a palindrome (942123121321249).
The spelling of 200112110110247 in words is "two hundred trillion, one hundred twelve billion, one hundred ten million, one hundred ten thousand, two hundred forty-seven".
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